What this data is telling me is that there are 1000 individuals in this given population. At the begging of the problem I am told that .731 is the value of q2, which are the homozygous recessive individuals. After that, I solve for q, then p, and then p2; which tells me the value of homozygous dominant inviduals
(.0225). Once I have the p,q, q2, and p2 values, finding the 2pq value is simple. What I have to do is multiple p times q and then multiply that product by 2. When I do this. I get that the value of 2pq (heterozygous individuals) is .255. However these values are frequencies, so you take each one, multiply it by 1000 and that tells me the number of individuals for each of the groups above. Therefore, there are
255 heterogeneous individuals,
731 homogeneous recessive
individuals and about 23 [when rounded] homogeneous dominant
individuals.
Tuesday, October 27, 2015
Hweezy Reasoning
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Hey Owen! So I think the process that you did was great, it's easy to understand and you can easily see what you're talking about, but in this part of the explanation it gets just a little confusing by what you're saying since the wording is a little tedious but overall I think it's really good :)
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