Hweezy Reasoning

What this data is telling me is that there are 1000 individuals in this given population. At the begging of the problem I am told that .731 is the value of q2, which are the homozygous recessive individuals. After that, I solve for q, then p, and then p2; which tells me the value of homozygous dominant inviduals
(.0225).  Once I have the p,q, q2, and p2 values, finding the 2pq value is simple. What I have to do is multiple p times q and then multiply that product by 2. When I do this. I get that the value of 2pq (heterozygous individuals) is .255. However these values are frequencies, so you take each one, multiply it by 1000 and that tells me the number of individuals for each of the groups above. Therefore, there are
255 heterogeneous individuals,
731 homogeneous recessive
individuals and about 23 [when rounded] homogeneous dominant 
individuals.

Hardy-Weinberg Blog

Step 1: Identify your given values.

·  Population: 1000

·  q2: .731

Step 2: Take the square root of q2 in order to solve for q.

·  √q2 = q

·  √.731 = .85

Step 3: Since the Hardy-Weinberg rule says that the sum of p and q is 1, then to find the value of p,
subtract q from 1. After that, you
square the p value to find the p2 value.

·  1-q=p

·  1-.85=.15

·  p2=.0225

Step 4: Once you have the p,q, q2, and p2 values, finding the 2pq value 
is simple. What you have to do is multiple p times q and them multiply that product by 2.

(p x q)(2) = 2pq
(.15 x .85)(2) = .255

Step 5: To find the number of  individuals in the population, you multiply each  of the values which stand for an individual (p2, q2, 2pq) bythe total number of individuals in the population.

(.255)(1000) = 255 heterogeneous individuals

(.731)(1000) = 731 homogeneous recessive individuals

(.0225)(1000) = about 23 [when rounded] homogeneous dominant individuals.

 ​