What this data is telling me is that there are 1000 individuals in this given population. At the begging of the problem I am told that .731 is the value of q2, which are the homozygous recessive individuals. After that, I solve for q, then p, and then p2; which tells me the value of homozygous dominant inviduals
(.0225). Once I have the p,q, q2, and p2 values, finding the 2pq value is simple. What I have to do is multiple p times q and then multiply that product by 2. When I do this. I get that the value of 2pq (heterozygous individuals) is .255. However these values are frequencies, so you take each one, multiply it by 1000 and that tells me the number of individuals for each of the groups above. Therefore, there are
255 heterogeneous individuals,
731 homogeneous recessive
individuals and about 23 [when rounded] homogeneous dominant
individuals.
Tuesday, October 27, 2015
Hweezy Reasoning
Hardy-Weinberg Blog
Step 1: Identify your given values.
· Population: 1000
· q2: .731
Step 2: Take the square root of q2 in order to solve for q.
· √q2 = q
· √.731 = .85
Step 3: Since the Hardy-Weinberg rule says that the sum of p and q is 1, then to find the value of p,
subtract q from 1. After that, you
square the p value to find the p2 value.
· 1-q=p
· 1-.85=.15
· p2=.0225
Step 4: Once you have the p,q, q2, and p2 values, finding the 2pq value
is simple. What you have to do is multiple p times q and them multiply that product by 2.
(p x q)(2) = 2pq
(.15 x .85)(2) = .255
Step 5: To find the number of individuals in the population, you multiply each of the values which stand for an individual (p2, q2, 2pq) bythe total number of individuals in the population.
(.255)(1000) = 255 heterogeneous individuals
(.731)(1000) = 731 homogeneous recessive individuals
(.0225)(1000) = about 23 [when rounded] homogeneous dominant individuals.
Saturday, September 12, 2015
California Black Worm Lab
To determine which of the different solutions (A,B,C) was which I applied my new knowledge from statistics. With the data we collected in class on Friday, I created three different
stemplots for substance A, B and C.
When I did that, I found that A had the highest values for number in the tens (eg. 11, 12 ...). This led me to conclude that Substance A was the depressant since the heart beat counts were so low.
When I created the stemplots for substances B and C, I found that they both had the highest values for numbers in the twenties (eg. 21, 22 ...). From here I concluded that substance C was the stimulant because it had more values in the 30s than substance be did. I also based my conclusion on my observations during the lab. When I was counting the heart beats of the worms in substance C I can remember that before I was able to get the worms out they were all almost fighting each other and all intertwined into a ball.
Therefore, this means that substance B is the water, because during the lab I also observed that these worms seemed to just swim calmly.
Thursday, July 30, 2015
APEEZY 3 Favorite Ecoloy Selfies at UCLA
| A Flower, #33 |
| A Non-flying Insect, #3 |
| A Population, #7 |


